x^2+x+45+x=325

Solution for x^2+x+45+x=325 equation:

x^2+x+45+x=325

We move all terms to the left:

x^2+x+45+x-(325)=0

We add all the numbers together, and all the variables

x^2+2x-280=0

a = 1; b = 2; c = -280;
Δ = b2-4ac
Δ = 22-4·1·(-280)
Δ = 1124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1124}=\sqrt{4*281}=\sqrt{4}*\sqrt{281}=2\sqrt{281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{281}}{2*1}=\frac{-2-2\sqrt{281}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{281}}{2*1}=\frac{-2+2\sqrt{281}}{2}
$